engineering mathematics MCQ #385

The distance between the foci of the hyperbola x²/9 - y²/16 = 1 is

engineering mathematics MCQ #385

  1. Question 1

    Q1. The distance between the foci of the hyperbola x²/9 - y²/16 = 1 is

    • A) 10
    • B) 5
    • C) 2√7
    • D) 2√5

    Answer: 10

    Explanation: For the hyperbola x²/a² - y²/b² = 1, the distance between foci is 2c, where c = √(a² + b²) = √(9 + 16) = 5.