engineering mathematics MCQ #390

The focus of the parabola x² = -8y is

engineering mathematics MCQ #390

  1. Question 1

    Q1. The focus of the parabola x² = -8y is

    • A) (0, -2)
    • B) (0, 2)
    • C) (2, 0)
    • D) (-2, 0)

    Answer: (0, -2)

    Explanation: For the parabola x² = -4ay, the focus is (0, -a), here 4a = 8, so a = 2.