engineering mathematics MCQ #391

The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at point (a secθ, b tanθ) is

engineering mathematics MCQ #391

  1. Question 1

    Q1. The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at point (a secθ, b tanθ) is

    • A) x secθ / a - y tanθ / b = 1
    • B) x secθ / a + y tanθ / b = 1
    • C) x tanθ / a - y secθ / b = 1
    • D) x tanθ / a + y secθ / b = 1

    Answer: x secθ / a - y tanθ / b = 1

    Explanation: The equation of the tangent to the hyperbola at point (a secθ, b tanθ) is x secθ / a - y tanθ / b = 1.