engineering mathematics MCQ #398

The parabola y² = 4ax passes through (2, 4), find 'a'

engineering mathematics MCQ #398

  1. Question 1

    Q1. The parabola y² = 4ax passes through (2, 4), find 'a'

    • A) 1 / 2
    • B) 2
    • C) 1
    • D) 4

    Answer: 2

    Explanation: Substitute (2, 4) into y² = 4ax to get 16 = 8a, then solve for 'a' to get a = 2.