The eccentricity of the ellipse x²/16 + y²/9 = 1 is
Question 1
Q1. The eccentricity of the ellipse x²/16 + y²/9 = 1 is
Answer: √7 / 4
Explanation: For ellipse x²/a² + y²/b² = 1, e = √(1 - b²/a²). Here, a² = 16, b² = 9, so e = √(1 - 9/16) = √7 / 4.