In how many ways can 5 boys and 3 girls be seated in a row so that no two girls are together?
Q1. In how many ways can 5 boys and 3 girls be seated in a row so that no two girls are together?
Answer: 14400
Explanation: First arranging 5 boys in 5! ways, then 3 girls in 6P3 ways. So, total = 5! * 6P3 = 14400.