In a box, there are 5 red, 4 blue, and 3 green balls. What is the probability of drawing a red ball first and then a blue ball?
Q1. In a box, there are 5 red, 4 blue, and 3 green balls. What is the probability of drawing a red ball first and then a blue ball?
Answer: 5 / 33
Explanation: P(red then blue) = P(red) * P(blue) = (5/12) * (4/11) = 5 / 33. Using multiplication rule.