In how many ways can 4 boys and 4 girls be seated in a row so that boys and girls are alternate?
Q1. In how many ways can 4 boys and 4 girls be seated in a row so that boys and girls are alternate?
Answer: 1152
Explanation: First, arrange 4 boys in 4! ways, then 4 girls in 4! ways. Total = 4! * 4! * 2 = 1152