engineering mathematics MCQ #404

The asymptotes of the hyperbola x²/9 - y²/16 = 1 are

engineering mathematics MCQ #404

  1. Question 1

    Q1. The asymptotes of the hyperbola x²/9 - y²/16 = 1 are

    • A) y = ±4x / 3
    • B) y = ±3x / 4
    • C) y = ±4x / √9
    • D) y = ±3x / √16

    Answer: y = ±4x / 3

    Explanation: For hyperbola x²/a² - y²/b² = 1, asymptotes are y = ±b/a*x. Here, a = 3, b = 4, so y = ±4x / 3.