engineering mathematics MCQ #405

The radius of the circle x² + y² + 4x - 6y + 4 = 0 is

engineering mathematics MCQ #405

  1. Question 1

    Q1. The radius of the circle x² + y² + 4x - 6y + 4 = 0 is

    • A) 3
    • B) √3
    • C) 4
    • D) √13

    Answer: 3

    Explanation: The given equation can be rewritten as (x + 2)² + (y - 3)² = 9, so radius = √9 = 3.