The equation of the tangent to the ellipse x²/16 + y²/9 = 1 at (2, 3√3 / 2) is
Q1. The equation of the tangent to the ellipse x²/16 + y²/9 = 1 at (2, 3√3 / 2) is
Answer: x / 8 + y√3 / 6 = 1
Explanation: The tangent to ellipse x²/a² + y²/b² = 1 at (a cosθ, b sinθ) is x cosθ / a + y sinθ / b = 1. Here, a = 4, b = 3.