The distance between the foci of the ellipse x²/100 + y²/36 = 1 is
Q1. The distance between the foci of the ellipse x²/100 + y²/36 = 1 is
Answer: 16
Explanation: For ellipse x²/a² + y²/b² = 1, distance between foci = 2√(a² - b²). Here, a² = 100, b² = 36, so distance = 2√64 = 16.