engineering mathematics MCQ #410

The eccentricity of the hyperbola x²/9 - y²/16 = 1 is

engineering mathematics MCQ #410

  1. Question 1

    Q1. The eccentricity of the hyperbola x²/9 - y²/16 = 1 is

    • A) 5 / 3
    • B) 4 / 3
    • C) 3 / 4
    • D) 3 / 5

    Answer: 5 / 3

    Explanation: For hyperbola x²/a² - y²/b² = 1, e = √(1 + b²/a²). Here, a² = 9, b² = 16, so e = √(1 + 16/9) = 5 / 3.