engineering mathematics MCQ #414

The center of the circle x² + y² - 4x + 6y - 3 = 0 is

engineering mathematics MCQ #414

  1. Question 1

    Q1. The center of the circle x² + y² - 4x + 6y - 3 = 0 is

    • A) (2, -3)
    • B) (-2, 3)
    • C) (2, 3)
    • D) (-2, -3)

    Answer: (2, -3)

    Explanation: The given equation can be rewritten as (x - 2)² + (y + 3)² = r², so center = (2, -3).