engineering mathematics MCQ #415

The equation of the hyperbola with foci (0, ±5) and transverse axis 8 is

engineering mathematics MCQ #415

  1. Question 1

    Q1. The equation of the hyperbola with foci (0, ±5) and transverse axis 8 is

    • A) y²/16 - x²/9 = 1
    • B) y²/9 - x²/16 = 1
    • C) x²/16 - y²/9 = 1
    • D) x²/9 - y²/16 = 1

    Answer: y²/16 - x²/9 = 1

    Explanation: For hyperbola, 2ae = distance between foci and 2a = transverse axis. Here, 2a = 8, 2ae = 10, so e = 5/4, b² = a²(e² - 1).