engineering mathematics MCQ #420

Find the center of the circle x² + y² - 4x + 6y - 3 = 0.

engineering mathematics MCQ #420

  1. Question 1

    Q1. Find the center of the circle x² + y² - 4x + 6y - 3 = 0.

    • A) (2, -3)
    • B) (-2, 3)
    • C) (4, -6)
    • D) (-4, 6)

    Answer: (2, -3)

    Explanation: Complete the square: (x-2)² + (y+3)² = 16. Center (2, -3).