engineering mathematics MCQ #423

The hyperbola x²/25 - y²/144 = 1 has foci at (±c, 0). What is c?

engineering mathematics MCQ #423

  1. Question 1

    Q1. The hyperbola x²/25 - y²/144 = 1 has foci at (±c, 0). What is c?

    • A) 13
    • B) 12
    • C) 11
    • D) 14

    Answer: 13

    Explanation: c² = a² + b² = 25 + 144 = 169 → c = 13.