engineering mathematics MCQ #426

What is the radius of the circle x² + y² - 4x + 6y - 12 = 0?

engineering mathematics MCQ #426

  1. Question 1

    Q1. What is the radius of the circle x² + y² - 4x + 6y - 12 = 0?

    • A) 5
    • B) √(12)
    • C) √(25)
    • D) √(7)

    Answer: 5

    Explanation: Complete the square: (x-2)² + (y+3)² = 25. Radius is √(25) = 5.