The value of k for which the equation x² + kx + 1 = 0 has real roots is?
Q1. The value of k for which the equation x² + kx + 1 = 0 has real roots is?
Answer: k ≥ 2 or k ≤ -2
Explanation: For real roots, the discriminant b² - 4ac ≥ 0. So, k² - 4*1*1 ≥ 0, hence k ≥ 2 or k ≤ -2.