The value of p for which the roots of x² + px + 2 = 0 are equal is?
Question 1
Q1. The value of p for which the roots of x² + px + 2 = 0 are equal is?
Answer: ±2√2
Explanation: For equal roots, the discriminant b² - 4ac = 0. So, p² - 4*1*2 = 0, hence p = ±2√2.