For what value of k, the equation x² + 2(k-1)x + k + 5 = 0 has real and equal roots?
Q1. For what value of k, the equation x² + 2(k-1)x + k + 5 = 0 has real and equal roots?
Answer: 1 or -4
Explanation: For equal roots, D = 0. So, 4(k-1)² - 4(k+5) = 0, simplifying to k² - 3k - 4 = 0, giving k = 1 or -4.