engineering mathematics MCQ #431

What is the radius of the circle x² + y² - 10x + 8y + 25 = 0?

engineering mathematics MCQ #431

  1. Question 1

    Q1. What is the radius of the circle x² + y² - 10x + 8y + 25 = 0?

    • A) 5
    • B) √(25 - 25 + 16) = 4
    • C) √(25 + 16 - 25) = 4
    • D) √(25 + 16) = √41

    Answer: √(25 + 16 - 25) = 4

    Explanation: Complete the square: (x-5)² + (y+4)² = 25 + 16 - 25 = 16 ⇒ Radius 4.