What is the eccentricity of the ellipse x²/16 + y²/25 = 1?
Question 1
Q1. What is the eccentricity of the ellipse x²/16 + y²/25 = 1?
Answer: √(25 - 16)/5 = 3/5
Explanation: Eccentricity e = √(a² - b²)/a. Here a²=25, b²=16 ⇒ e=√(25-16)/5 = 3/5.