engineering mathematics MCQ #434

Find the foci of the hyperbola x²/9 - y²/16 = 1.

engineering mathematics MCQ #434

  1. Question 1

    Q1. Find the foci of the hyperbola x²/9 - y²/16 = 1.

    • A) (±5, 0)
    • B) (±4, 0)
    • C) (±√7, 0)
    • D) (±3, 0)

    Answer: (±5, 0)

    Explanation: For hyperbola x²/a² - y²/b² = 1, foci at (±c, 0) where c² = a² + b² ⇒ c=5.