engineering mathematics MCQ #453

What are asymptotes of hyperbola x²/16 - y²/9 = 1?

engineering mathematics MCQ #453

  1. Question 1

    Q1. What are asymptotes of hyperbola x²/16 - y²/9 = 1?

    • A) y = ±(3/4)x
    • B) y = ±(4/3)x
    • C) y = ±(2/3)x
    • D) y = ±(3/2)x

    Answer: y = ±(3/4)x

    Explanation: Asymptotes of x²/a² - y²/b² =1 are y = ±(b/a)x → b/a = 3/4.