engineering mathematics MCQ #455

Find the directrix of parabola x² = 20y.

engineering mathematics MCQ #455

  1. Question 1

    Q1. Find the directrix of parabola x² = 20y.

    • A) y = 5
    • B) y = -5
    • C) x = 5
    • D) x = -5

    Answer: y = -5

    Explanation: Standard form x² = 4ay → 4a = 20 → a = 5. Directrix is y = -a = -5.