For ellipse x²/25 + y²/16 = 1, foci are located at:
Question 1
Q1. For ellipse x²/25 + y²/16 = 1, foci are located at:
Answer: (±3, 0)
Explanation: c² = a² - b² = 25 - 16 = 9 ⇒ c = 3. Foci on x-axis at (±3, 0).