engineering mathematics MCQ #462

Asymptotes of hyperbola y²/9 - x²/16 = 1 are:

engineering mathematics MCQ #462

  1. Question 1

    Q1. Asymptotes of hyperbola y²/9 - x²/16 = 1 are:

    • A) y = ±(3/4)x
    • B) y = ±(4/3)x
    • C) y = ±(9/16)x
    • D) y = ±(16/9)x

    Answer: y = ±(4/3)x

    Explanation: Asymptote slopes = ±(b/a) for vertical transverse axis: ±(3/4) → y = ±(3/4)x.