The equation of the tangent to the parabola y² = 4ax at (at², 2at) is
Q1. The equation of the tangent to the parabola y² = 4ax at (at², 2at) is
Answer: ty = x + at²
Explanation: The tangent to y² = 4ax at (at², 2at) is given by ty = x + at², using the point-slope form and the slope at the given point.