engineering mathematics MCQ #466

The eccentricity of the hyperbola x²/a² - y²/b² = 1 is

engineering mathematics MCQ #466

  1. Question 1

    Q1. The eccentricity of the hyperbola x²/a² - y²/b² = 1 is

    • A) √(1 + b²/a²)
    • B) √(1 - b²/a²)
    • C) √(a² + b²)/a
    • D) √(a² - b²)/a

    Answer: √(1 + b²/a²)

    Explanation: For the hyperbola x²/a² - y²/b² = 1, b² = a²(e² - 1), so e = √(1 + b²/a²).