engineering mathematics MCQ #473

The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at (asecθ, btanθ) is

engineering mathematics MCQ #473

  1. Question 1

    Q1. The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at (asecθ, btanθ) is

    • A) (x secθ)/a - (y tanθ)/b = 1
    • B) (x tanθ)/a - (y secθ)/b = 1
    • C) (x cosθ)/a - (y sinθ)/b = 1
    • D) (x sinθ)/a - (y cosθ)/b = 1

    Answer: (x secθ)/a - (y tanθ)/b = 1

    Explanation: The tangent to the hyperbola at (asecθ, btanθ) is given by (x secθ)/a - (y tanθ)/b = 1, derived using the point-slope form.