engineering mathematics MCQ #490

The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at (a secθ, b tanθ) is

engineering mathematics MCQ #490

  1. Question 1

    Q1. The equation of the tangent to the hyperbola x²/a² - y²/b² = 1 at (a secθ, b tanθ) is

    • A) (x/a)secθ - (y/b)tanθ = 1
    • B) (x/a)secθ + (y/b)tanθ = 1
    • C) (x/b)secθ - (y/a)tanθ = 1
    • D) (x/b)secθ + (y/a)tanθ = 1

    Answer: (x/a)secθ - (y/b)tanθ = 1

    Explanation: The tangent equation is (x/a)secθ - (y/b)tanθ = 1, derived using the point (a secθ, b tanθ).