engineering mathematics MCQ #4951

The general solution of 2sin(3x) + 1 = 0 is

engineering mathematics MCQ #4951

  1. Question 1

    Q1. The general solution of 2sin(3x) + 1 = 0 is

    • A) nπ/3 + (-1)^(n+1) * π/18
    • B) nπ + (-1)^(n+1) * π/6
    • C) nπ/3 + (-1)^n * π/18
    • D) nπ + (-1)^n * π/6

    Answer: nπ/3 + (-1)^(n+1) * π/18

    Explanation: sin(3x) = -1/2, hence 3x = nπ + (-1)^(n+1) * π/6, so x = nπ/3 + (-1)^(n+1) * π/18.