engineering mathematics MCQ #502

For hyperbola x²/16 - y²/9 = 1, the distance between foci is

engineering mathematics MCQ #502

  1. Question 1

    Q1. For hyperbola x²/16 - y²/9 = 1, the distance between foci is

    • A) 10
    • B) 8
    • C) 6
    • D) 4

    Answer: 10

    Explanation: Distance is 2c where c² = a² + b² ⇒ c = √(16 + 9) = 5 ⇒ 2c = 10.