engineering mathematics MCQ #503

The directrix of ellipse x²/25 + y²/16 = 1 is

engineering mathematics MCQ #503

  1. Question 1

    Q1. The directrix of ellipse x²/25 + y²/16 = 1 is

    • A) x = ±25/3
    • B) x = ±5/3
    • C) x = ±3/5
    • D) x = ±1/5

    Answer: x = ±25/3

    Explanation: Directrices for horizontal ellipse are x = ±a/e. Here e = 3/5, so a/e = 25/3.