Eccentricity of a hyperbola with vertices at (±3,0) and foci at (±5,0):
Question 1
Q1. Eccentricity of a hyperbola with vertices at (±3,0) and foci at (±5,0):
Answer: 1.66
Explanation: e = c/a = 5/3 ≈ 1.66 where c² = a² + b².