The range of f(x) = 2sin(x) + 1 is?
Question 1
Q1. The range of f(x) = 2sin(x) + 1 is?
Answer: [-1, 3]
Explanation: The range of sin(x) is [-1, 1], so the range of 2sin(x) is [-2, 2] and the range of 2sin(x) + 1 is [-2 + 1, 2 + 1] = [-1, 3].