engineering mathematics MCQ #5267

If sin(A) = 3/5 and cos(B) = 4/5, then sin(A+B) =

engineering mathematics MCQ #5267

  1. Question 1

    Q1. If sin(A) = 3/5 and cos(B) = 4/5, then sin(A+B) =

    • A) 24/25
    • B) 7/25
    • C) 1
    • D) 0

    Answer: 24/25

    Explanation: Using sin(A+B) = sin(A)cos(B) + cos(A)sin(B). We need to find cos(A) and sin(B) using Pythagorean identity.