engineering mathematics MCQ #527

The hyperbola x²/25 - y²/16 = 1 has foci at (±c, 0). What is c?

engineering mathematics MCQ #527

  1. Question 1

    Q1. The hyperbola x²/25 - y²/16 = 1 has foci at (±c, 0). What is c?

    • A) 3
    • B) 4
    • C) 5
    • D) √41

    Answer: √41

    Explanation: For hyperbola c² = a² + b² = 25 + 16 = 41 → c = √41.