The eccentricity of the hyperbola x²/9 - y²/16 = 1 is?
Question 1
Q1. The eccentricity of the hyperbola x²/9 - y²/16 = 1 is?
Answer: 5/3
Explanation: For x²/a² - y²/b² = 1, e = √(1 + b²/a²). Here, e = √(1 + 16/9) = √(25/9) = 5/3.