engineering mathematics MCQ #550

What is the center of the circle described by x² + y² + 6x - 8y - 11 = 0?

engineering mathematics MCQ #550

  1. Question 1

    Q1. What is the center of the circle described by x² + y² + 6x - 8y - 11 = 0?

    • A) (-3, 4)
    • B) (3, -4)
    • C) (-4, 3)
    • D) (4, -3)

    Answer: (-3, 4)

    Explanation: Group terms and complete the square: (x + 3)² + (y - 4)² = 30. Center is (-3, 4).