engineering mathematics MCQ #560

The radius of the circle x² + y² - 4x + 6y - 3 = 0 is:

engineering mathematics MCQ #560

  1. Question 1

    Q1. The radius of the circle x² + y² - 4x + 6y - 3 = 0 is:

    • A) 4
    • B) 5
    • C) 6
    • D) 7

    Answer: 4

    Explanation: Complete the square: (x-2)² + (y+3)² = 4 + 9 + 3 = 16 ⇒ radius 4.