engineering mathematics MCQ #578

For hyperbola x²/16 - y²/9 = 1, asymptotes are y = ±(b/a)x. What is b/a?

engineering mathematics MCQ #578

  1. Question 1

    Q1. For hyperbola x²/16 - y²/9 = 1, asymptotes are y = ±(b/a)x. What is b/a?

    • A) 3/4
    • B) 4/3
    • C) 5/4
    • D) 4/5

    Answer: 3/4

    Explanation: Asymptotes slope b/a = 3/4 from standard form x²/a² - y²/b² = 1.