engineering mathematics MCQ #584

Foci of hyperbola x²/16 - y²/9 = 1 lie along:

engineering mathematics MCQ #584

  1. Question 1

    Q1. Foci of hyperbola x²/16 - y²/9 = 1 lie along:

    • A) x-axis
    • B) y-axis
    • C) both axes
    • D) origin

    Answer: x-axis

    Explanation: Hyperbola foci alignment matches transverse axis. x² term positive → x-axis.