engineering mathematics MCQ #598

The equation of a circle with center (2, -3) and radius 5 is

engineering mathematics MCQ #598

  1. Question 1

    Q1. The equation of a circle with center (2, -3) and radius 5 is

    • A) (x-2)² + (y+3)² = 25
    • B) (x+2)² + (y-3)² = 5
    • C) (x-2)² + (y+3)² = 5
    • D) (x+2)² + (y+3)² = 25

    Answer: (x-2)² + (y+3)² = 25

    Explanation: Standard circle equation (x-h)² + (y-k)² = r². Subtract h and k from x and y. Radius squared is 25.