engineering mathematics MCQ #605

If y = sin(x²), find dy/dx

engineering mathematics MCQ #605

  1. Question 1

    Q1. If y = sin(x²), find dy/dx

    • A) 2x cos(x²)
    • B) cos(x²)
    • C) 2x sin(x²)
    • D) x cos(x)

    Answer: 2x cos(x²)

    Explanation: Using chain rule, dy/dx = d(sin(x²))/dx = cos(x²) * d(x²)/dx = 2x cos(x²)