engineering mathematics MCQ #627

If y = cos(3x), then dy/dx = ?

engineering mathematics MCQ #627

  1. Question 1

    Q1. If y = cos(3x), then dy/dx = ?

    • A) -3 sin(3x)
    • B) 3 sin(3x)
    • C) -sin(3x)
    • D) sin(3x)

    Answer: -3 sin(3x)

    Explanation: Using chain rule, dy/dx = -sin(3x) * d(3x)/dx = -sin(3x) * 3 = -3 sin(3x).