engineering mathematics MCQ #646

If y = x²e^(x), find dy/dx

engineering mathematics MCQ #646

  1. Question 1

    Q1. If y = x²e^(x), find dy/dx

    • A) x²e^(x) + 2xe^(x)
    • B) x²e^(x) - 2xe^(x)
    • C) xe^(x) + 2x²e^(x)
    • D) xe^(x) - 2x²e^(x)

    Answer: x²e^(x) + 2xe^(x)

    Explanation: Using product rule, dy/dx = x²d(e^(x))/dx + e^(x)d(x²)/dx = x²e^(x) + 2xe^(x)