If y = log(x + √(x² + 1)), find dy/dx
Question 1
Q1. If y = log(x + √(x² + 1)), find dy/dx
Answer: 1 / √(x² + 1)
Explanation: Using chain rule, dy/dx = 1/(x + √(x² + 1)) * d(x + √(x² + 1))/dx = 1/√(x² + 1)