engineering mathematics MCQ #663

If y = x³e^x, find dy/dx

engineering mathematics MCQ #663

  1. Question 1

    Q1. If y = x³e^x, find dy/dx

    • A) x³e^x + 3x²e^x
    • B) x³e^x - 3x²e^x
    • C) 3x²e^x
    • D) x³e^x

    Answer: x³e^x + 3x²e^x

    Explanation: Using product rule, dy/dx = x³e^x + 3x²e^x